Electric Charge and Force

We started the day understanding about electric charges. We use a baloon to find out the relationship. When a baloon is rubbed on a fur, then put on a glass wall, it gets stuck to the wall glass. This is caused by the negative charge being taken out by the fur and leaving it with positive charge, which sticks to the negative charge of the glass wall.

When the baloon is rubbed on a silk, then put on the glass wall, the baloon seems to pushes away from the glass and fall. This is because silk is taking away the negative charge slower than fur, when it actually should have stuck to the glass as well.

Recall from 4a, we learned about forces and free body diagram. First, we are finding the angle by using its relationship with the length of the string. Then, by drawing the free body diagram, we find the sum of forces in x and y directions, then find the force to move the person hanging on the string. Then we replace the angle using what we found earlier.

From 4A, we have learned about universal gravitational force, where G is multiplied by the 2 masses and r of 1&2, divided by the difference of distance squared.

Using that formula, we can solve the given problem below and found the result to force to be 1.35*10^-4 J.

We can see the relationship between force and r as inversely proportional, the bigger the difference between 2 masses, the smaller the Force and vice versa.

When talking about 2 charges, we can also use the same equation by replacing the masses with the charges. We can find the components of forces by finding the angle of the charges. Using that angle and multiply them by the force will give us wach forces and adding them to find the vector force.